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    Question

    A man works twice as efficiently as a woman and three

    times as efficiently as a child. If 3 men and 4 children can complete a task in 18 days, how long would it take for 6 women to finish the same task?
    A 24 days Correct Answer Incorrect Answer
    B 20 days Correct Answer Incorrect Answer
    C 13 days Correct Answer Incorrect Answer
    D 26 days Correct Answer Incorrect Answer

    Solution

    Let the efficiency of a child be '2x' units/day So, efficiency of a man = 2x X 3 = '6x' units/day And, efficiency of a woman = 6x ÷ 2 = '3x' units/day Work done by 3 men and 4 children in 18 days = {(6x X 3) + (4 X 2x)} X 18 = (18x + 8x) X 18 = '468x' units So, time taken by 6 women to do the same work = 468x ÷ (3x X 6) = 26 days

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