Question
A and B can each finish a task in 32 days and 36 days
respectively. They begin the task together, but after 12 days, A leaves. How long will it take for B to complete the remaining work alone?Solution
Let total amount of work = 288 units (LCM of 32 and 36) Amount of work done by A in one day = 288/32 = 9 units Amount of work done by B in one day = 288/36 = 8 units Amount of work done by A and B together in 12 days = 12 × 17 = 204 units Remaining work = 288 – 204 = 84 units Desired time = 84/8 = 10.5 days Hence, option c.
45.45 × 11.67 + 14399.88 ÷ 8.01 + 124.79 = ?
(48/16)2 × 50/50 ÷ 50/800 = ? Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(1177.99 + 226.99 + 94.923) ÷ 24.97% of 59.989 = ?
1459.98 ÷ 40.48 × 12.12 = ? × 3.16
(44.85% of 639.79 + 3/8 of 480.23) × (√63.84 – 19.99% of 499.71) = ?
33.02% of (143.92 + 7 × ?) + 34.03 = 99.88
2550.03 ÷ 74.98 x 49.9 = ? + 20.32
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