Question
'A' can complete a certain task in 60 days, while 'B'
can do the same in 45 days. 'A' starts the task and works alone for 18 days, after which 'B' joins him. How many more days will it take to finish the remaining work?Solution
Let the total amount of the work = 180 units = LCM of (60 and 45) Efficiency of ‘A’ = 180/60 = 3 units Efficiency of ‘B’ = 180/45 = 4 units Amount of the work done by ‘A’ alone in 18 days = (18 × 3) = 54 units Remaining work = (180 – 54) = 126 units Required time taken = {126/(3 + 4)} = 18 days
More Time and work Questions
(30 × 0.80)⁴ ÷ (2160 ÷ 60)⁴ × (54 × 16)⁴ = (6 × 4)?+5
3/7 of 504 ÷ 12 + 17 = √?
20% of 150 + 30 X 4 = ? X 5
52% of 400 + √(?) = 60% of 600 - 25% of 400
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
15 * 12 + 35% of 80 + 70% of 130 = ?
60 % of 640 - 57 × 2 - 1520 / 38 = ?
- Find the simplified value of the given expression:
10 of 5 ÷ 4 × 2² + √25 – 8 (168 ÷ 12 + 19 × 64)/(22+1) = ?
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