Question
'A' can complete a certain task in 60 days, while 'B'
can do the same in 45 days. 'A' starts the task and works alone for 18 days, after which 'B' joins him. How many more days will it take to finish the remaining work?Solution
Let the total amount of the work = 180 units = LCM of (60 and 45) Efficiency of βAβ = 180/60 = 3 units Efficiency of βBβ = 180/45 = 4 units Amount of the work done by βAβ alone in 18 days = (18 Γ 3) = 54 units Remaining work = (180 β 54) = 126 units Required time taken = {126/(3 + 4)} = 18 days
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