Question
G' can complete (3/4) of a job in 24 days, while 'G'
and 'H' together can complete the same job in 16 days. Find the time taken by 'H' to complete 25% of the job alone.Solution
ATQ, Time taken by 'G' to complete the whole job alone = 24×( 4/3)=32 days Let the total amount of work = LCM of 32 and 16 = 96 units Efficiency of 'G' =96/32 = 3 units per day Efficiency of (G + H) = 96/16= 6 units per day Efficiency of 'H' = 6−3 = 3 units per day Desired time = (0.25 × 96/3) = 8 days
If cos(90° − θ) = 3/5 for an acute angle θ, find:
Simplify:
15cos 41° cosec 49° - 6tan 55° tan 35°What is the value of [(sin x + sin y) (sin x – sin y)]/[(cosx + cosy) (cosy – cosx)]?
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If 6sin²x + 2cos²x − 3 = 0, then find the value of sinx, given that 0° < x < 90°.
- Find the simplified value of the expression:sin 2 45 o  + sin 2 60 o  - (1/3) X tan 2 60 o
If x+  1/x = 2cosθ, then the value of x³+  1/x³ is
- If 4cos²A + 5sin²A = 4.5, then find the value of (sec²A - 1)

The Value of (sin38Ëš)/(cos52Ëš) + (cos12Ëš)/(sin78Ëš) - 4cos²60Ëš is