Question
Rohan can finish a task alone in 24 days. Shreya can do
50% of the same task alone in 12 days. If Shreya and Tanya work together, they can complete 60% of the task in 9 days. Find the time taken by Rohan and Tanya to finish the task together.Solution
ATQ, Time taken by Shreya to do the entire task = 12 Ă· 0.5 = 24 days Time taken by Shreya and Tanya to do the entire task together = 9 Ă· 0.6 = 15 days Let the total work be 120 units {LCM (24, 24, and 15)} So, the combined efficiency of Shreya and Tanya = 120 Ă· 15 = 8 units/day Efficiency of Shreya = 120 Ă· 24 = 5 units/day Efficiency of Tanya = 8 - 5 = 3 units/day Efficiency of Rohan = 120 Ă· 24 = 5 units/day So, required time taken = 120 Ă· (5 + 3) = 120 Ă· 8 = 15 days
Glucose is a type of
Source of oxygen during photosynthesis is
Highest water use efficiency is of
Which of the following plants requires a long uninterrupted dark period to flower?
The Structural and functional unit of chromosome is termed as
What structure controls the opening and closing of stomata?
Which statement about transpiration is true?
In linkage process,  Acetyl CoA is formed by the oxidative decarboxylation of ____
In the following given options, What is the importance of mitosis cell division?
When plant cells are placed in hypertonic solution, they become____
Relevant for Exams:
