Question
Armaan and Bhanu working together can finish a certain
task in 90 days, and Bhanu collaborating with Chintu can complete the same task in 70 days. If Armaan's efficiency is 40% less than Chintu, determine the time Armaan alone needs to complete 80% of the work.Solution
ATQ, Let the total work be 630 units. (LCM of 90 and 70) Amount of work done by Armaan and Bhanu together in one day = 630/90 = 7 units Amount of work done by Bhanu and Chintu together in one day = 630/70 = 9 units Difference between the efficiencies of Armaan and Chintu = 9 – 7 = 2 units Amount of work done by Chintu alone in one day = 2/0.40 = 5 units Amount of work done by Armaan alone in one day = 0.6 × 5 = 3 units Time taken by Armaan alone to complete 80% work = 0.8 × 630/3 = 168 days
24, 12, 18, ?, 157.5, 708.75
5 11 32 65 ? 389
...14Â Â 16Â Â Â 20Â Â Â 15Â Â 25Â Â Â Â 13Â Â Â 29Â Â Â 9Â Â Â 32Â Â Â 6
...640Â Â Â Â 322Â Â Â Â Â 164Â Â Â Â Â Â 86Â Â Â Â Â 48Â Â Â Â Â ?
...Select the number from among the given options that can replace the question mark (?) in the following series.
2, 6, 12, 20, ?, ?
123   125   129   132   ?   145
218, 108, 160, ? , 1385.50
412, 537, 573, 916, 980, ?
If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...462 478 510 558 ?
...
Relevant for Exams:
