Question
Armaan and Bhanu working together can finish a certain
task in 90 days, and Bhanu collaborating with Chintu can complete the same task in 70 days. If Armaan's efficiency is 40% less than Chintu, determine the time Armaan alone needs to complete 80% of the work.Solution
ATQ, Let the total work be 630 units. (LCM of 90 and 70) Amount of work done by Armaan and Bhanu together in one day = 630/90 = 7 units Amount of work done by Bhanu and Chintu together in one day = 630/70 = 9 units Difference between the efficiencies of Armaan and Chintu = 9 – 7 = 2 units Amount of work done by Chintu alone in one day = 2/0.40 = 5 units Amount of work done by Armaan alone in one day = 0.6 × 5 = 3 units Time taken by Armaan alone to complete 80% work = 0.8 × 630/3 = 168 days
If for non-zero x, x² - 4x - 1 = 0, what is the value of x² + 1/x²?
If, ( a + b = 14 ) and ( a² + b² = 106 ), then find the value of (a³ + b³).
If x2 – 10x + 20 = 0, then find the value of (x – 3)2 + 1/(x – 3)2
If x + 1/x = 5 then find out the value of x⁵ + 1/(x⁵)?
What is the value of (a² + b²+4c²- ab-2bc-2ca) (a + b+2c):
(a+2 )² + (b-5)² + (c+3)² = 0
Find the value of √ (a + b + c) ?
...x = 7 - 4√3 then the value of x³+1/x³ is equal to?
If 2x + y = 10 and 3x - 2y = 5, find the value of x + y.
If ab = -15 and (a2 + b2) = 34, then find the value of (a – b).
If x, y, z are the three factors of a 3– 7a – 6, then value of x + y + z will be
Relevant for Exams:
