Question
P, Q, and R can complete a work in 12 days. 15 days and
30 days, respectively, working alone. How soon can the work be completed if P is assisted by Q and R on alternate days?ΒSolution
Total work = 60 (LCM of 12, 15 and 30) P's efficiency = 60/12 = 5 Q's efficiency = 60/15 = 4 R's efficiency = 60/30 = 2 Pattern of work = PQ, PR, PQ, PR... Work done by PQ and PR in 2 days = (5 + 4) + (5 + 2) = 16 2 days => 16 units 2 Γ 3 = 6 days => 16 Γ 3 = 48 units remaining in 12 units done by PQ in = work/efficiency = 9/ (5 + 4) = 1 days Total time taken = 6 + 1 = 7 days Now remaining 3unit work done by PR = 3/5+2=3/7day 7+3/7 =52/7days.
Select the word-pair in which the two words are related in the same way as the two words in the following word-pair.
Painter : Painting
By interchanging the given two signs which of the following equation will be not correct?
Γ and β
Statements:
X < W β€ F = Q β₯ P = T β₯O β₯ S = R
Conclusions:
I) Q > R
I) Q = R
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(520, 8, 56)
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Select the combination of letters that when sequentially placed in the blanks of the given letter series will complete the series.
_ K L _ N O J ...
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E @ G = 37 : L @ D = 50 :: H @ K = 90 : : P @ F = ?
Find the odd set of numbers from the given alternatives?