Question
P, Q, and R can complete a work in 12 days. 15 days and
30 days, respectively, working alone. How soon can the work be completed if P is assisted by Q and R on alternate days?ÂSolution
Total work = 60 (LCM of 12, 15 and 30) P's efficiency = 60/12 = 5 Q's efficiency = 60/15 = 4 R's efficiency = 60/30 = 2 Pattern of work = PQ, PR, PQ, PR... Work done by PQ and PR in 2 days = (5 + 4) + (5 + 2) = 16 2 days => 16 units 2 × 3 = 6 days => 16 × 3 = 48 units remaining in 12 units done by PQ in = work/efficiency = 9/ (5 + 4) = 1 days Total time taken = 6 + 1 = 7 days Now remaining 3unit work done by PR = 3/5+2=3/7day 7+3/7 =52/7days.
What should come in place of (?) question mark in the given number series.
81, 73, 66, 60, 55, ?
14 6 4 4 ? 48
...What should come in place of (?) question mark in the following number series.
5, 11, 23, 47, 95, ?
In each of the following number series, one term is missing. Find the missing term.
1, 4, 9, 16, 25, ?
What will come in place of the question mark (?) in the following series?
4, 11, 32, 95, 284, 851, ?
156, 182, 210, 240, 272, ?
31    32      35      ?      47       56
...What should come in place of (?) question mark in the following number series.
1, 2, 6, 24, 120, ?
What value should come in the place of (?) in the following number series?
71, 72, 76, 103, ?, 244254, ?, 1022, 1150, 1214, 1246
