Question
‘A’ can do 30% of the work in 12 days. ‘B’ can
do the whole work in 50 days. Find the time taken by them together to do 75% of the work.Solution
Time taken by ‘A’ to complete the whole work. = 12/0.30 = 40 days Time taken by ‘B’ to complete the whole work. = 50 days Let total work = 200 units (LCM of 50and 40) Efficiency of ‘A’ = 200/40 = 5 units/day Efficiency of ‘B’ = 200/50 = 4 units/day required time taken = (.75×200)/ (5+4) =150/9=16.66days
28 × 3.5 +25 × 3.2 = ? - 62
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
3.2% of 500 × 2.4% of ? = 288
414 ÷ 23 × 38 – 154 + 264 = ?
...What will come in the place of question mark (?) in the given expression?
{(16 × 25) ÷ 32} × 12 = ? – 200
[(4/3) + (5/6)] of 378 = ?
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4 Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
What will come in the place of question mark (?) in the given expression?
(55 × 8 + 28) × 10 = ?
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