Question
βAβ can do 30% of the work in 12 days. βBβ can
do the whole work in 50 days. Find the time taken by them together to do 75% of the work.Solution
Time taken by βAβ to complete the whole work. = 12/0.30 = 40 days Time taken by βBβ to complete the whole work. = 50 days Let total work = 200 units (LCM of 50and 40) Efficiency of βAβ = 200/40 = 5 units/day Efficiency of βBβ = 200/50 = 4 units/day required time taken = (.75Γ200)/ (5+4) =150/9=16.66days
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