Question
A can complete a task 40% more efficiently in 25 days,
whereas B, with a 25% efficiency boost, can finish the same task in 21 days. They collaborated at their original efficiencies for 9 days. Now, how we can determine the time it will take for A to complete the remaining work, reverting to his original efficiency level when working alone.Solution
ATQ, Let total amount of work be 525 units Amount of work done by βAβ in one day (with increased efficiency) = 525/25 = 21units Original efficiency of βAβ = 21/1.40 = 15 units per day Amount of work done by βBβ in one day (with increased efficiency) = 525/21 = 25units Original efficiency of βBβ = 25/1.25 = 20 units per day Amount of work completed by βAβ and βBβ together in 9 days = 35 Γ 9 = 315 units Remaining work = 525 β 315 = 210 units Desired time = 210/15 = 14 day
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