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ATQ, The efficiency ratio of Ishita and Evita is = 3:2 Let the number of days taken by Ishita alone be ‘2d’ days and that by Evita be ‘3d’ days respectively. Ishita alone worked for 10 days and Evita worked for 9 days out of 19 later they are working on alternate days. = 10×(1/2d) + (1/3d) = 1 on solving we get d= 8 Then, Evita alone will take (3 x 8) days to do work = 24 days. The required number of days (24 x 48)/(24 + 48) = 16 days
Find the value of (cos 60 º + sin 60 º) /(tan 60 º + cot 45 º) .
If sin θ = 3/5 and cos θ = 4/5, find the value of (2tan² θ + 3cot² θ).
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, then determine the value of (4A - B).
If sin 28° = 15/17 , then tan 62° = ?
tan 1˚ × tan 2˚× …………………….tan 88˚ × tan 89˚ = ?
If 2cosA + secA = 2√2 , 0° < < 90°, then the value of 2(sec 4 A + cosec 4 A) is: