Question
A can complete a work in 30 days. B takes 6 days less
than A to complete the same work. In how many days can both of them together complete 90% of the work together?Solution
Time taken by B to complete the work = 30 â 6 = 24 days Let the total work = 120 units Efficiency of A = 120/30 = 4 units/day Efficiency of B = 120/24 = 5 units/day Required time taken = 0.90 x 120/(4+5) = 12 days
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