Question
βAβ alone can complete a work in 10 days. βBβ
alone can complete the same work in 15 days. If βAβ and βBβ work together for 3 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 30 units {LCM of 10 and 15} Then, efficiency of βAβ = 30/10 = 3 units/day Efficiency of βBβ = 30/15 = 2 units/day Combined efficiency of βAβ and βBβ = 3 + 2 = 6 units/day Work completed by βAβ and βBβ together in 3 days = 5 Γ 3 = 15 units Remaining work = 30 β 15 = 15 units Time taken by βAβ alone to complete the remaining work = 15/3 = 5 days
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