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    Question

    The time taken by тАШAтАЩ to build a wall alone is 40%

    more than the time taken by him to build it along with тАШBтАЩ. тАШBтАЩ will take how much percent more time to build the same wall than the time taken by him to build it along with тАШAтАЩ?
    A 220% Correct Answer Incorrect Answer
    B 230% Correct Answer Incorrect Answer
    C 250% Correct Answer Incorrect Answer
    D 210% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the work тАШAтАЩ and тАШBтАЩ, can do in 1 day be тАШaтАЩ units and тАШbтАЩ units, respectively. Let they takes тАШpтАЩ days to build the wall, together Therefore, Total work = (a + b) ├Ч p units тАжтАж.. (1) According to the question, Time taken by тАШAтАЩ to build the wall alone = 1.4p days Therefore, total work = 1.4p ├Ч a unitsтАж.. (2) From equation (1) and (2), we get 2.5b = a Therefore, total work to be done = (a + b) ├Ч p = 3.5bp units Time taken by 'B' to build the wall = 3.5bp/b = 3.5p days Therefore, required percentage = (3.5p тАУ p)/p} ├Ч 100 = 250% more time

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