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    Question

    The time taken by β€˜A’ to build a wall alone is 45%

    more than the time taken by him to build it along with β€˜B’. β€˜B’ will take how much percent more time to build the same wall than the time taken by him to build it along with β€˜A’?
    A 202.22% Correct Answer Incorrect Answer
    B 111.11% Correct Answer Incorrect Answer
    C 222.22% Correct Answer Incorrect Answer
    D 333.33% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the work β€˜A’ and β€˜B’, can do in 1 day be β€˜a’ units and β€˜b’ units, respectively. Let they takes β€˜p’ days to build the wall, together Therefore, Total work = (a + b) Γ— p units …….. (1) According to the question, Time taken by β€˜A’ to build the wall alone = 1.45p days Therefore, total work = 1.45p Γ— a units….. (2) From equation (1) and (2), we get 20b/9 = a Therefore, total work to be done = (a + b) Γ— p = 29bp/9 units Time taken by 'B' to build the wall = 29bp/9b = 29p/9 days Therefore, required percentage = (29p/9 – p)/p} Γ— 100 = 222.22% more time

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