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Let the total work = 240 units Then, efficiency of ‘A’ = (240/20) = 12 units/hour Work completed by ‘A’ alone in 15 hours = 12 × 15 = 180 units Remaining work = 240 – 180 = 60 units So, efficiency of ‘B’ = 60/20 = 3 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 3 + 12 = 15 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (240/15) = 16 hours
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