Question
‘A’ alone can complete a work in 20 hours. ‘A’
started the work alone and left after working on it for 15 hours. If ‘B’ completed the rest of the work in 20 hours then find the time taken by ‘A’ and ‘B’ together to complete the whole work.Solution
Let the total work = 240 units Then, efficiency of ‘A’ = (240/20) = 12 units/hour Work completed by ‘A’ alone in 15 hours = 12 × 15 = 180 units Remaining work = 240 – 180 = 60 units So, efficiency of ‘B’ = 60/20 = 3 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 3 + 12 = 15 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (240/15) = 16 hours
(1550.23 ÷ 30.98) + (864.32 ÷ 23.9) + 1724.11 = ?
? = 21.91% of (36.2 × (144.01 + 5.95)) + 16.71
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(12.13) 2 - 19.93 + 39.78 - 42.93 = ?
(6859.01)1/3 × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(29.98% of 9840) + ? + (19.899% of 8490) = 7560
Bijay can complete a task on his own in 40 days, while Ajay can finish the same task in 25 days. If they alternate working on the...
– (8.002)³ + (30.001)² - (4.01)⁴ =?
31% of 3300 +659 = ?
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