‘A’ alone can complete a work in 20 hours. ‘A’ started the work alone and left after working on it for 15 hours. If ‘B’ completed the rest of the work in 20 hours then find the time taken by ‘A’ and ‘B’ together to complete the whole work.
Let the total work = 240 units Then, efficiency of ‘A’ = (240/20) = 12 units/hour Work completed by ‘A’ alone in 15 hours = 12 × 15 = 180 units Remaining work = 240 – 180 = 60 units So, efficiency of ‘B’ = 60/20 = 3 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 3 + 12 = 15 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (240/15) = 16 hours
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