Question
βAβ and βBβ can do a piece of work in 22 days
and 25 days, respectively. If they started the work together and worked on it for 6 days, then find the time taken by βBβ alone to complete the remaining work.Solution
Let total amount of work be 550 unitsΒ Efficiency of βAβ = 550/22 = 25 units/day Efficiency of βBβ = 550/25 = 22 units/day Amount of work done by βAβ and βBβ together in 6 days = (25 + 22) Γ 6 = 282 units Time taken by B to complete remaining work = (550 β 282)/22 = 134/11 days
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