Question
Average speed of βAβ during a 26-hour journey is 26
km/h. If he covered the first 120 km of his journey at a speed of 20 km/h, then find the speed at which βAβ travelled during the remaining journey.Solution
Total distance covered by βAβ = 26 Γ 26 = 676 km Time taken to cover 120 km = 120/20 = 6 hours Time taken to cover remaining distance = 26 β 6 = 20 hours So, required speed = {(676 β 120)/20} = 27.8 km/h
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