A, B, and C together can do a work alone in 14 days, 35 days, and 70 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?
Total work = LCM of 14, 35 and 70 = 70 units Unit per day of A = 70/14 = 5 Unit per day of B = 70/35 = 2 Unit per day of C = 70/70 = 1 Units of work done by A in 3 days = 5 × 3 = 15 units Units of work done by B in 8 days = 8 × 2 = 16 units Remaining work = 70 – (15 + 16) = 39 units So, C has worked for 39/1 = 39 days
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