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Start learning 50% faster. Sign in nowLet the total work = L.C.M of 40 and 30 = 120 units Then, efficiency of ‘A’ alone = 120 ÷ 40 = 3 units/day Combined efficiency of ‘A’ and ‘B’ = 120 ÷ 30 = 4 units/day So, efficiency of ‘B’ = 4 – 3 = 1 units/day So, work done by ‘B’ alone in 66 days = 1 × 66 = 66 units So, percentage of work completed by ‘B’ = (66 ÷ 120) × 100 = 55%
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