‘A’ alone can complete a work in 40 days while ‘A’ and ‘B’ together can complete the same work in 30 days. How much percentage of the work, ‘B’ alone can complete in 66 days?
Let the total work = L.C.M of 40 and 30 = 120 units Then, efficiency of ‘A’ alone = 120 ÷ 40 = 3 units/day Combined efficiency of ‘A’ and ‘B’ = 120 ÷ 30 = 4 units/day So, efficiency of ‘B’ = 4 – 3 = 1 units/day So, work done by ‘B’ alone in 66 days = 1 × 66 = 66 units So, percentage of work completed by ‘B’ = (66 ÷ 120) × 100 = 55%
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