Question
An elephant can do a work as fast as two horses ‘A’
and ‘B’ can do it by working together. If horse ‘A’ alone can complete the work in 9 hours and horse ‘B’ in 18 hours, then find the time taken by elephant to complete the work.Solution
Let the total work = 18 units Efficiency of horse who can complete the work in 9 hours = 18/9 = 2 units/hour Efficiency of horse who can complete the work in 18 hours = 18/18 = 1 units/hour Therefore, time taken by both horses to complete the work together = 18/(2 + 1) = 6 hours Therefore, time taken by the elephant to complete the work = 6 hours
6000 3002 1503 ? 378.75 191.375 97.6875
...1, 27, ?, 343, 729, 1331
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
51 53 109 332 ? 6686
...9 4.5 4.5 9 36 ?
5 16 ? 66 119 200
...1 1 8 4 27 9 ?
...What will be the next number in the series?
2, 7, 23, 70, ?
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044
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