Question
Karan, Arjun and Krunal alone can complete a work in 40,
60 and 48 days respectively. All of them started working together but after 3 days from start Karan left the job and after 5 more days Arjun also left the job. So for how many days did Krunal work?Solution
Let the total work = 240 units (LCM of 40, 60 and 48) Amount of work done by Karan alone in one day = 240/40 = 6 units Amount of work done by Arjun alone in one day = 240/60 = 4 units Amount of work done by Krunal alone in one day = 240/48 = 5 units Amount of work done by Karan, Arjun and Krunal together in 3 days = 3 × (6 + 4 + 5) = 45 units Amount of work done by Arjun and Krunal together in 5 days = 5 × (4 + 5) = 45 units Remaining work = 240 – 45 – 45 = 150 units So, the time taken by Krunal alone to complete 60 units work = 150/5 = 30 days So, Krunal worked for 30 + 5 + 3 = 38 days
6000 3002 1503 ? 378.75 191.375 97.6875
...1, 27, ?, 343, 729, 1331
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
51 53 109 332 ? 6686
...9 4.5 4.5 9 36 ?
5 16 ? 66 119 200
...1 1 8 4 27 9 ?
...What will be the next number in the series?
2, 7, 23, 70, ?
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044