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Let the total work = L.C.M of 15 and 10 = 30 units Then, efficiency of ‘A’ alone = 30 ÷ 15 = 2 units/day Combined efficiency of ‘A’ and ‘B’ = 30 ÷ 10 = 3 units/day So, efficiency of ‘B’ = 3 – 2 = 1 units/day So, work done by ‘B’ alone in 21 days = 1 × 21 = 21 units So, percentage of work completed by ‘B’ = (21 ÷ 30) × 100 = 70%
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