Question
βAβ alone can complete a work in 15 days while
βAβ and βBβ together can complete the same work in 10 days. How much percentage of the work, βBβ alone can complete in 21 days?Solution
Let the total work = L.C.M of 15 and 10 = 30 units Then, efficiency of βAβ alone = 30 Γ· 15 = 2 units/day Combined efficiency of βAβ and βBβ = 30 Γ· 10 = 3 units/day So, efficiency of βBβ = 3 β 2 = 1 units/day So, work done by βBβ alone in 21 days = 1 Γ 21 = 21 units So, percentage of work completed by βBβ = (21 Γ· 30) Γ 100 = 70%
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