Question
‘A’ alone can complete a work in 60 days while
‘A’ and ‘B’ together can complete the same work in 42 days. How much percentage of the work, ‘B’ alone can complete in 63 days?Solution
Let the total work = L.C.M of 60 and 42 = 420 units Then, efficiency of ‘A’ alone = 420 ÷ 60 = 7 units/day Combined efficiency of ‘A’ and ‘B’ = 420 ÷ 42 = 10 units/day So, efficiency of ‘B’ = 10 – 7 = 3 units/day So, work done by ‘B’ alone in 63 days = 3× 63 = 189 units So, percentage of work completed by ‘B’ = (189 ÷ 420) × 100 = 45%
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