Question
βAβ alone can complete a work in 45 days while
βAβ and βBβ together can complete the same work in 35 days. How much percentage of the work, βBβ alone can complete in 63 days?Solution
Let the total work = L.C.M of 45 and 35 = 315 units Then, efficiency of βAβ alone = 315 Γ· 45 = 7 units/day Combined efficiency of βAβ and βBβ = 315 Γ· 35 = 9 units/day So, efficiency of βBβ = 9 β 7 = 2 units/day So, work done by βBβ alone in 63 days = 2 Γ 63 = 126 units So, percentage of work completed by βBβ = (126 Γ· 315) Γ 100 = 40%
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