Question
‘A’ can do a piece of work in 15 days. ‘B’ can
do 60% of the same work in 20 days. If they work together for the entire time and get paid Rs.1450, then find the share of ‘A’.Solution
Let the total work be 60 units. (LCM of 15 and 20) Efficiency of A = 60/15 = 4 units/day Efficiency of B = (60/20) × (60/100) = 9/5 units/day Ratio of the efficiency of A : B = 4 : 9/5 = 20:9 Share of A = (20/29) × 1450 = Rs.1000
If total number of factors of 3,240 is 'x', then find the value of (x - 3)(x + 5).
HCF of two numbers 65 and 104 can be expressed in the form of (40m – 107) whereas LCM of these two numbers can be expressed in the form of (60n – 20...
Three numbers are in the ratio 3:7:2 respectively. If the HCF of the numbers is 5, then find the LCM of the numbers.
The least number which when divided by 16, 32 and 48 leave remainder 4, 20 and 36 respectively is?
The least number which when divided by 4, 8, 10 and 12 leave zero remainder in each case and when divided by 13 leaves a remainder of 9 is:
The HCF of two numbers is 6 and their LCM is 84. If one of these numbers is 42, then the second number is:
The HCF of two numbers is 72, and their LCM is 2160. What is the sum of the numbers?
LCM of two numbers is 12 times their HCF. The product of the numbers is 25920. What will be the maximum possible difference between the numbers?
The ratio of two numbers is 6:14 and their LCM is 126. The numbers are:
- The L.C.M and H.C.F of two numbers have a sum and difference of 440 and 120. If one number is 40, find the other.
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