Question
A and B together, B and C together and A and C together
can complete a piece of work in 80 days, 60 days and 70 days respectively. Find the ratio of the efficiencies of A, B and C, respectively.Solution
Let, the total work be 1680 units (LCM of 80, 60 and 70) Amount of work done by A and B together in one day = 1680/80 = 21 units Amount of work done by B and C together in one day = 1680/60 = 28 units Amount of work done by A and C together in one day = 1680/70 = 24 units Amount of work done by A, B and C together in one day = (21 + 28 + 24)/2 = 36.5 units Amount of work done by A alone in one day = 36.5 – 28 = 8.5 units Amount of work done by B alone in one day = 36.5 – 24 = 12.5 units Amount of work done by C alone in one day = 36.5 – 21 = 15.5 units So the desired ratio = 17:25:31
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