Question
A and B together, B and C together and A and C together
can complete a piece of work in 80 days, 60 days and 70 days respectively. Find the ratio of the efficiencies of A, B and C, respectively.Solution
Let, the total work be 1680 units (LCM of 80, 60 and 70) Amount of work done by A and B together in one day = 1680/80 = 21 units Amount of work done by B and C together in one day = 1680/60 = 28 units Amount of work done by A and C together in one day = 1680/70 = 24 units Amount of work done by A, B and C together in one day = (21 + 28 + 24)/2 = 36.5 units Amount of work done by A alone in one day = 36.5 – 28 = 8.5 units Amount of work done by B alone in one day = 36.5 – 24 = 12.5 units Amount of work done by C alone in one day = 36.5 – 21 = 15.5 units So the desired ratio = 17:25:31
(350/?) = 23 + 33
(630 ÷ 35) × 2 + 144 = ? × 2
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
236.23-653.23+696.23=?
72 × 2 = ? + 104 – 14
36895 - 4256 - 2233 = ?
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)? = 15% of 2400 + 140% of 4200 – 12 3
√121 + √961− √289 =?2
