A and B together, B and C together and A and C together can complete a piece of work in 88 days, 66 days and 72 days respectively. Find the ratio of the efficiencies of A, B and C, respectively.
A4:5:7Correct AnswerIncorrect Answer
B4:3:7Correct AnswerIncorrect Answer
C4:7:5Correct AnswerIncorrect Answer
D7:5:4Correct AnswerIncorrect Answer
E4:2:7Correct AnswerIncorrect Answer
Solution
Let, the total work be 792 units (LCM of 88, 66 and 72)
Amount of work done by A and B together in one day = 792/88 = 9 units
Amount of work done by B and C together in one day = 792/66 = 12 units
Amount of work done by A and C together in one day = 792/72 = 11 units
Amount of work done by A, B and C together in one day = (9 + 12 + 11)/2 = 16 units
Amount of work done by A alone in one day = 16 – 12 = 4 units
Amount of work done by B alone in one day = 16 – 11 = 5 units
Amount of work done by C alone in one day = 16 – 9 = 7 units
