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    Question

    Abhishek, Rohit and Pankaj working together completed a

    job in 20 days. The ratio of their efficiencies is 3 : 4 : 5. How many days will be required by the fastest worker alone to complete the whole work?
    A 17 days Correct Answer Incorrect Answer
    B 48 days Correct Answer Incorrect Answer
    C 37 days Correct Answer Incorrect Answer
    D 73 days Correct Answer Incorrect Answer

    Solution

    Ratio of efficiencies = 3 : 4 : 5 & they together completed a job in 20 days. So let total work = (3+4+5)`xx` 20 = 240 units So fastest person will do the job in = 240/5 = 48 days

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