Question
A cyclist starts from village 'M' at 8:00 AM towards village 'N' at 20 km/h. A biker starts from 'M' at 9:30 AM in the same direction at 60 km/h. Find the time when the biker catches the cyclist.
Solution
ATQ,
Distance between cyclist and biker when biker starts = 20 × 1.5 = 30 km
Relative speed = 60 − 20 = 40 km/h
Time taken by biker to catch up = 30 / 40 = 0.75 hours = 45 minutes
Required time = 9:30 AM + 45 minutes = 10:15 AM
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