Question
A man goes to his office at 7.2 km/h and returns at 9 km/h.
If the total time for the round trip is 80 minutes, find the distance between his home and office.Solution
ATQ,
Let the distance between his home and office be βdβ km.
ATQ,
(d/7.2) + (d/9) = (80/60)
Or, (5d/36) + (4d/36) = (4/3)
Or, (9d/36) = (4/3)
So, d = (36 Γ 4) / (3 Γ 9) = 144 / 27 = 5.33
So, the distance between his home and office = d = 5.33 km
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