Question
A train crosses a man and a platform that is 480 meters
long in 12 seconds and 36 seconds, respectively. Given this information, calculate the speed of the train. Consider that when the train crosses a man, it only covers its own length, while when crossing the platform, it must cover both its length and the length of the platform. What will be the speed of the train in meters per second?Solution
Let the length of train = x meter Speed of the train = x/12 Again, when train crosses the platform Then, speed = (x+480)/36 x/12 = (x+480)/36 3x = x+480 x = 240 m speed of train = 240/12 = 20 m/s = 20×18/5 = 72 km/h
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