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ATQ, Let the length of the Toll plaza be 't' metres Speed of Truck = 180 × 5/18 = 50 m/s According to the question, (200 + t)/50 = 10 Or, t = 300 metres Length of the second Truck = 300 – 180 = 120 metres Speed of the Truck = 252 × (5/18) = 70 m/s Therefore, (300 + 120)/70 = 6 seconds
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