Question
A and B are travelling towards each other with a speed
of 20 km/hr and 30 km/hr. They started at same time and A covered 30 km less distance than B before meeting B. Find the distance between them before starting.Solution
Here time taken by both A and B is same, so the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 20:30 = 2:3 Let the distance covered by A and B be 2x km and 3x km respectively. According to question, => 3x – 2x = 30 => x = 30 Therefore, distance between them before starting = 3x + 2x = 5x = 150 km
If x + y + z = 20, x² + Y² + z² = 160 and x z = y², then find the value of x z?
if a2 + b2 + c2Â =Â 2(3a -5b -6c)-70 , then a-b-c = ?
If sin 28° = 15/17 , then tan 62° = ?
If ab = -15 and (a2 + b2) = 34, then find the value of (a – b).
(123×123×123 + 130×130×130)/(123×123 - 123×130 + 130×130) = ?Â
 = ? (√ (sec2 θ + cosec2 θ )) ((sinθ (1 + cosθ ))/(1 + cos&thet...
If z + (1/z) = 2 then find z105 + 1/(z105) = ?
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