Question
βAβ and βBβ started moving towards each other at
same time with a speed of 24 km/hr and 12 km/hr, respectively. If the distance covered by βAβ is 15 km more than that by βBβ, when they meet then find the initial distance between them.Solution
Ratio of distance travelled by βAβ and βBβ = 24:12 = 2:1 Required distance = 15 Γ 3 = 45 km
More Time and distance Questions
5 + 2 Γ 3 Γ· (3 Γ 2) Γ· 4
What will come in the place of question mark (?) in the given expression?
(β1089 + β484) X 5 + ? = 725
Simplify the following expression:
44% of 1250 + 46 Γ 34 = 40% of ? + 1154
The value of 3 Γ 7 + 5 β 6 Γ· 3 β 9 + 45 Γ· 5 Γ 4 β 45 Β is:
35% of 500 × 22% of ? = 847
((9.77)0- γ(0.1)γ(-1))/(γ(6/24 )γ(-1)Β Γ(3/2)3+ γ((-2)/6)γ(-1) ) = ?
...- What will come in place of (?) in the given expression.
(14)Β² β (12)Β² = ? 20 + 160/? Γ 20 = 420
2048 × 1824 ÷ 76 = (? - 212) × 64
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