Question
A cheetah can catch a deer running with a speed of 72
km/h and is 72 meters ahead of it, in 8 seconds. Find the time taken by the cheetah to catch a zebra that is 195 metres ahead of it and is running with a speed which is 70% of that of the deer.Solution
Speed of the deer = 72 km/h = 72 × (5/18) = 20 m/s Distance covered by the cheetah in 8 seconds = 72 metres + distance covered by the deer in 8 seconds = 72 + 20 × 8 = 72 + 160 = 232 metres So, speed of the cheetah = 232/8 = 29 m/s Speed of the zebra = 20 × (70/100) = 14 m/s So, relative speed of the cheetah with respect to the zebra = 29 – 14 = 15 m/s Hence, time taken by the cheetah to catch the zebra = 195/15 = 13 seconds
If ‘#’ denotes ‘-‘, @ denotes ‘×’, ‘$’ denotes ‘+’ and ‘%’ denotes ‘÷’, then
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