Question
1470 metres long train crosses a man who is moving in
the same direction with a certain speed, in 30 seconds. If the same train can cross a tree in 7 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 1470/7 = 210 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (210 β s) m/sec According to the question, (210 β s) = 1470/30 Or, s = 210 β 49 = 161 Therefore, speed of the man = 161 m/sec
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