Question
The speed of a bike increases by 3 km/hr after every 1
hour. If the distance travelled by the bike in 1st hour is 24 km, the find the total distance travelled by the bike in 10 hours.Solution
Since, the speed of the bike increases by 3 km/hr after every 1 hour, therefore the bike will travel 3 km extra after every 1 hour. Therefore, distance travelled by the bike in 1st hour = 24 km Distance travelled by the bike in 2nd hour = 24 + 3 = 27 km Distance travelled by the bike in 3rd hour = 27 + 3 = 30 km This form an AP i.e. 24, 27, 30β¦β¦β¦distance travelled in 16th hour Therefore, total distance travelled by the bike in 10 hours = sum of the AP Distance travelled in 10 hours = (n/2){2a + (n β 1)d} Where n = number of terms = 10, a = 1st term = 24 and d = common difference = 3 Therefore, distance travelled in 10 hours = (10/2){2 Γ 24 + (10 β 1) Γ 3} = (10/2)(48 + 27) = 375 km
15(2/9) + 11(2/9) + 17(1/9) + 13(4/9) = ?
25% of 1000 + 10% of 150 β 22 Γ ? = 45
1885 ÷ 64.98 + 7.29 + ? = 69.09
βAβ and βBβ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, βAβ withdrew 25% of his initial investment...
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
What value should come in place of (?) question mark.
β2025 β β729 + (24 Γ 32) Γ· 6 = ?
What will come in the place of question mark (?) in the given expression?
(30% of 1200 + 50% of 3200) Γ· 98 = ?
(?) + (35)2 = (140)2 – (80)2 + 20% of 5480
7292/3 = ?