A train moving at 3/5th of its normal speed reaches its destination 10 hours late. Find the normal time taken by it.
Let the speed and time be s and t respectively. New speed = 3/5 s and new time = t + 10 According to the question, S × t = 3/5 s(t + 10) St =3/5 st + 6s 5st = 3st + 30s 2st = 30s T = 15 hrs. Alternate Method: Speed ratio = 1: 3/5 = 5:3 So time ratio = 3:5 so here time gap in ratio = 5-3 = 2 ==> 10 1 ==>5 So actual time = 3*5 = 15 hrs
Which of the following is the code of ‘action’?
In a certain code language, ‘PLATTER’ is coded as ‘7312259’ and ‘MARINE’ is coded as ‘419955’. How will HERITAGE’ be coded in that lan...
In a certain language, the word WHERE is written as 24 – 9 – 7 – 19 – 7. How will you write GROSS in the same language?
What is the code for ‘Happy’?
If ‘DOG’ = 78, then ‘BARK’ = (?)
In a certain coded language 'DRUM' is coded as 'AOVI' and 'VARY' is coded as 'UBOU', then what is the code of ' AUTO '?
Which of the following may be the code for ‘other the happy’?
What does the code “5%J 9*N 8#C” stands for?
In a certain code language ‘TRAIN’ is written as ‘SUAOJ’ and ‘SPAIN’ is written as ‘QTAOJ’. How is ‘GRAIN’ written in that code?
In a certain code language, ‘NET’ is written as '78' and 'ERA' is written as '48'. How will 'KIT' be written in that language?