Question
A train moving at 3/5th of its normal speed reaches its destination 10 hours late. Find the normal time taken by it.
Solution
Let the speed and time be s and t respectively. New speed = 3/5 s and new time = t + 10 According to the question, S × t = 3/5 s(t + 10) St =3/5 st + 6s 5st = 3st + 30s 2st = 30s T = 15 hrs. Alternate Method: Speed ratio = 1: 3/5 = 5:3 So time ratio = 3:5 so here time gap in ratio = 5-3 = 2 ==> 10 1 ==>5 So actual time = 3*5 = 15 hrs
More Time and distance Questions
- A cyclist is 1,200 metres ahead of a motorbike when the motorbike starts chasing at 25 m/s. If the cyclist is riding at 15 m/s, then find the time taken by...
- A man travels some distance at a speed of 12 km/hr and returns at a speed of 9 km/hr. If the total time taken by him is 4 hrs 40 min, the distance is
- A man travels from Town A to Town B at 40 km/h and returns from B to A at 60 km/h by the same route. What is his average speed for the whole journey?
- Due to fog, the speed of a train was reduced to (2/3)rd of its original speed, resulting in a delay of 45 minutes. Find the usual time taken by the train t...
- Amit covered 360 kilometers in total trip time. He covered the remaining 200 km on a bicycle at a speed that was 5 km/h slower than that of the bus after t...
- A car covers 135 km in 3 hours. The scooter is 2.5 m/s slower than the car. Find the scooter’s distance (in metres) in 5 minutes.
- A boy goes to school with a speed of 70 km/h and comes back with a speed of 55 km/h. find his average speed?
- ‘A’ and ‘B’ started moving towards each other at same time with a speed of 27 km/hr and 15 km/hr, respectively. If the distance covered by ‘A’ is 36 km mor...
- The average speed of a bus is 5/7 of the average speed of a car which covers 2800 km in 50 hrs. What is the average speed of the bus?
- A cyclist goes 30 km at speed x km/h and returns 30 km at speed (x - 5) km/h. Total time taken is 5 hours. Find x.
Relevant for Exams:
