Question
The speeds of Avinash and Rahul are 70km/hr and 90km/hr.
Initially Rahul is at a place P and Avinash is at a place Q. The distance between Rahul and Avinash is 1040km. Avinash started his journey 8 hours earlier than Rahul to meet each other. If they meet each other at a place O somewhere between P and Q, then the distance between O and Q isSolution
Let the distance covered of x km by Avinash Time taken is ‘t’ hours, then Distance covered by Avinash= speed × time x = 70 × t ………………………(i) Distance covered by Rahul (1040 - x)km by Rahul. Distance covered by Rahul = speed × time (1040 – x) = 90 × (t – 8) ………………………(ii) Putting the value of ‘t’ in eq (ii) from eq (i) (1040 – x) = 90 × (x/70 – 8) 1040 - x = 9x/7 – 720 1040 + 720 = 9x/7 + x 1760 = 16x/7 x = 770 km
?% of 320 = 40% of 40 × 5
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
42% of 400 + 38% of 800 + ?2 = 728
What will come in place of (?) in the given expression.
{(60% of 250) + √144} ÷ (3² - 4) = ?- What will come in place of (?) in the given expression.
√324 + √121 – √49 = ? Determine the simplified value of following expression:
0.998 + 0.882 + 0.12Â
√225 + 27 × 10 + ? = 320
(26)2 = {(20% of 40% of 18200) ÷ ?} × 1664 ÷ 128Â
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
What is the value of 143 + 163 + 183 + … + 303?
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