The speeds of Avinash and Rahul are 70km/hr and 90km/hr. Initially Rahul is at a place P and Avinash is at a place Q. The distance between Rahul and Avinash is 1040km. Avinash started his journey 8 hours earlier than Rahul to meet each other. If they meet each other at a place O somewhere between P and Q, then the distance between O and Q is
Let the distance covered of x km by Avinash Time taken is ‘t’ hours, then Distance covered by Avinash= speed × time x = 70 × t ………………………(i) Distance covered by Rahul (1040 - x)km by Rahul. Distance covered by Rahul = speed × time (1040 – x) = 90 × (t – 8) ………………………(ii) Putting the value of ‘t’ in eq (ii) from eq (i) (1040 – x) = 90 × (x/70 – 8) 1040 - x = 9x/7 – 720 1040 + 720 = 9x/7 + x 1760 = 16x/7 x = 770 km
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