Question
The value of ((1024)n/5 ×
42n+1)/( 16n × 4n-1 )Solution
(γ(1024)γ^(n/(5 )) × 4^(2n+1))/(γ16γ^(n ) × 4^(n- 1) ) ⇒ (γ(4β΅)γ^(n/5) × 4^(2n+1))/(4^2n × γ4 γ^(n-1) ) ⇒ (4^(n+2n+1) )/(4^(2n+n- 1) ) ⇒ (4^(3n+1) )/(4^(3n- 1) ) ⇒ 4^(3n+1-3n+1) ⇒ 4² = 16
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