Question
Evaluate 32 ÷ 2 of 7 of [14 ÷ 7 of (6 ÷ 3 +
5)] + (6 ÷ 2 + 1)Solution
ATQ, = 32 ÷ 2 of 7 of [14 ÷ 7 of (6 ÷ 3 + 5)] + (6 ÷ 2 + 1) = 32 ÷ 2 of 7 of [14 ÷ 7 of (2 + 5)] + (3 + 1) = 32 ÷ 2 of 7 of [14 ÷ 7 of 7] + 4 = 32 ÷ 2 of 7 of [14 ÷ 49] + 4 = 32 ÷ 2 of 7 of [2/7] + 4 = 32 ÷ [2 of 7 of 2/7] + 4 = 32 ÷ [2 of (7 × 2/7)] + 4 = 32 ÷ [2 of 2] + 4 = 32 ÷ 4 + 4 = 8 + 4 = 12
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