Question
118 × 6 + 13 + 83 =
? Simplify the following questions:Solution
118 × 6 + 13 + 83 = ? ? = 708 + 13 + 83 ? = 804
(408 × 680)÷(20% of 680) = (250 × 260)÷ 10 + ? – 4500
If [8(x + y)3 – 27(x – y)3] ÷ (5y – x) = Ax2 + Bxy + Cy2, then the value of (A2 - 2B + 3C)...
- If [5a - (1/2a)] = 7, then find the value of [25a² + (1/4a²) - 3]
If
= 2 then find If √b + (1/√b) = 11, then find the value of b + (1/b).
When positive numbers x, y and z are divided by 31, the remainders are 17, 24 and 27, respectively. When (4x - 2y + 3z) is divided by 31, the remainder ...
- If (x 2 = 8x - 16), then find the value of [x³ + (x⁴/16)][4 - x³]
- 42.5% of 20% of 960 = x + 18.4, then find the sum of the squares of each digit in 'x'.
If 125x3 - 64y3 = (Ax + By) (Dy2 - Cx2 + 20xy) , then the value of A + C - 2B + 3D is:
If 0.125x3 +0.216y3 = 210 and 0.25x2 + 0.36y2 = 10.30 then find the value of 0.5x + 0.6y.