Question
A man invests a total of ₹50,000 in two schemes A and
B. Scheme A offers simple interest at 12% p.a. for 3 years. Scheme B offers compound interest at 10% p.a., compounded annually, for 2 years. The interest earned from scheme B exceeds the interest earned from scheme A by ₹1,380. How much money did he invest in scheme B?Solution
Let amount invested in Scheme A = ₹x ⇒ in Scheme B = ₹(50,000 − x) Interest from A (SI): Rate = 12%, Time = 3 years Interest_A = x × 12 × 3 / 100 = 0.36x Interest from B (CI): Rate = 10%, Time = 2 years CI factor = (1.10)² − 1 = 1.21 − 1 = 0.21 Interest_B = 0.21(50,000 − x) Given: Interest_B − Interest_A = 1,380 0.21(50,000 − x) − 0.36x = 1,380 10,500 − 0.21x − 0.36x = 1,380 10,500 − 0.57x = 1,380 0.57x = 10,500 − 1,380 = 9,120 x = 9,120 / 0.57 = 16,000 So, investment in Scheme B = 50,000 − 16,000 = ₹34,000
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