Question
Amit invested Rs. 20,000 at simple interest of 10% p.a. If
he withdrew Rs. 4,000 after every one year, then find the total interest earned by Amit at the end of three years. [Consider that the interest is payable at the end of three years only]Solution
Simple interest = Sum × Rate × Time ÷ 100
So, interest earned in the first year
= 20000 × 10 × 1 ÷ 100 = Rs. 2000
Interest earned in the second year
= (20000 − 4000) × 10 × 1 ÷ 100 = Rs. 1600
Interest earned in the third year
= (20000 − 8000) × 10 × 1 ÷ 100 = Rs. 1200
So, total interest earned = 2000 + 1600 + 1200 = Rs. 4,800
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4 What will come in the place of question mark (?) in the given expression?
√4096 + √3249 = (?)2
Simplify the following expressions and choose the correct option.
(96 ÷ 8 + 72 ÷ 9) * 3
((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
{(5/8) + (4/5)} × (?/19) = 33
(72 × 52 + 1555 )/(79+60) = 2000 ÷ ?
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
- What will come in place of (?) in the given expression.
(14)² – (12)² = ? What value should come in the place of (?) in the following questions?
√(60 + 82 + 101) * 5 = ?
