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      Question

      Rs. 2,750 is invested in three parts all at simple

      interest of 7% p.a. These three parts are invested randomly for 1 year, 2 years and 3 years such that the interest received from the given three parts after desired period of investment is same. Find the difference between the smallest and the largest part of the investment.
      A Rs. 1,000 Correct Answer Incorrect Answer
      B Rs. 900 Correct Answer Incorrect Answer
      C Rs. 750 Correct Answer Incorrect Answer
      D Rs. 800 Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Let the amount invested in three parts be Rs. ‘p’, Rs. ‘q’ and Rs. ‘r’ ATQ; (p × 0.07 × 1) = (q × 0.07 × 2) = (r × 0.07 × 3) Or,
      p = 2q = 3r Let p = 2q = 3r = ‘6t’ So,
      p = 6t
      q = 3t
      r = 2t So,
      p + q + r = 2750 Or,
      6t + 3t + 2t = 2750 Or,
      11t = 2750 Or,
      t = 250 So, required difference = 6t − 2t = 4t = 4 × 250 = Rs. 1,000

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