Question
A principal amount of ₹5p grows
to ₹(5p + 660) in 2 years at an annual interest rate of 20% compounded yearly. Determine the compound interest earned when ₹30p is invested for 1 year at an annual interest rate of 30%, compounded semi-annually.Solution
ATQ, 5p(1+20/100)2 = 5p+660 5p(120/100)2 = 5p+660 5p(6/5)2 = 5p+660 5p(36/25) = 5p+660 36p = 25p+3300 p = Rs.300 30p = Rs.9000 Required answer = 9000[(1+15/100)2 -1] = Rs.2902.5
(18 2 – 17 2) x (1/5) + ? = 148
- Find the simplified value of the given expression:
10 of 5 ÷ 4 × 2² + √25 – 8 40 of 30% of 220 = ? + 790
?² = 37% of 800 – 14 × 18+ 5! - 20
3/7 of 686 + 133(1/3)% of 33 – 69 =?
What will come in the place of question mark (?) in the given expression?
(12.09)2 × 5.98 ÷ 26.95 = ? + 25
350% of (450 / 1.5) = ?% of 4200
12 × 6 + 24 – 36 of 5 + 160 = ?
150% of ? + 280 ÷ 35 = 132 - 122 + 7