ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!

    Question

    Rs. 4,600 is invested in three parts all at simple

    interest of 10% p.a. These three parts are invested randomly for 1 year, 3 years and 5 years such that the interest received from the given three parts after desired period of investment is same. Find the difference between the smallest and the largest part of the investment.
    A Rs. 2,400 Correct Answer Incorrect Answer
    B Rs. 2,000 Correct Answer Incorrect Answer
    C Rs. 2,200 Correct Answer Incorrect Answer
    D Rs. 1,800 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the amount invested in three parts be Rs. тАШpтАЩ, Rs. тАШqтАЩ and Rs. тАШrтАЩ ATQ; (p ├Ч 0.10 ├Ч 1) = (q ├Ч 0.10 ├Ч 3) = (r ├Ч 0.10 ├Ч 5) Or,
    p = 3q = 5r Let p = 3q = 5r = тАШ15tтАЩ So,
    p = 15t
    q = 5t
    r = 3t So,
    p + q + r = 4600 Or,
    15t + 5t + 3t = 4600 Or,
    23t = 4600 Or,
    t = 200 So, required difference = 15t тИТ 3t = 12t = 12 ├Ч 200 = Rs. 2,400

    Practice Next
    More Simple and compound interest Questions

    Relevant for Exams:

    ask-question