Question
Diksha invested Rs. x in a scheme that offers compound
interest at a rate of 31.25% per annum, compounded annually. The difference between the amount she receives after 3 years and 2 years is Rs. 22,050. Determine the initial investment value, x.Solution
Given rate of interest = 31.25% = (5/16)
Amount received from compound interest = P X (1 + rate/100) time
So, amount received after 2 years = x X {1 + (5/16) }2 = Rs. {x X (21/16) 2}
Amount received after 3 years = x X {1 + (5/16) }3 = Rs. {x X (21/16) 3}
ATQ,
{x X (21/16) 3} - {x X (21/16) 2} = 22050
Or, x X (21/16) 2 X (21 - 16) = 22050 X 16
Or, x = 22050 X (16/5) X (256/441)
So, 'x' = 40,960
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
56 x 8 – 65% of 40 = ? + 14 x √625
240 + 25% of 420 – 145 =? + (2.5 + 8.5) 2
If 28957.5 ÷ 268.125= 108, then 289.575 ÷ 2681.25 is equal to:
? = (22% of 25% of 60% of 3000) + 21
? ÷ [35% of 379 - 34(4/5)] = 0.4
420 ÷ 7 + 140 % of 20 + ? × 13 = 18 × 15
[4(2/3) + 5(1/6)] × 45% of 240 = ?
What will come in the place of question mark (?) in the given expression?Â
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...182 – 517 ÷ 11 - √361 = ?