A farmer wants to divide Rs 1,22,000 between his sons ,

Solution

Let the farmer give Rs x to the 18 years old son and the remaining Rs (1,22,000 - x) to his 20 years old son. Now, 〖x(1+20/100)〗^4 = (1,22,000 - x) (1+20/100)^2 ⇒〖x(120/100)〗^2 = (1,22,000 - x)   ⇒ 〖x(6/5)〗^2 = (1,22,000 - x)   ⇒ x(36/25) = (1,22,000 - x) ⇒ (36/25+1) x = 1,22,000 ⇒ ((36 + 25)/25) x = 1,22,000 ⇒ x = (1,22,000 × 25)/61 = 50,000 ∴ x = Rs 50,000 For 18 years old son = Rs 50,000 For 20 years old son = Rs 72,000 Alternate shortcut method: They will get the sum in 2nd to 1st child in the ratio  of = (1+R/100)^(difference between their age)=(1+20/100)^(20-18)=(6/5)^2=36/25 So for 18 years old(1st child)  , sum = 25/(36+25)×102000=25/51×102000=50000 & for 20 years old(2nd child)  , sum = 36/(36+25)×102000=36/51×102000=72000