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Let the sum invested be Rs. 'P'. ATQ; 3850 - P = {(P X 12 X 54)/(12 X 100)} Or, 3850 - P = (27P/50) Or, (3850 - P) X 50 = 27P Or, 3850 X 50 - 50P = 27P Or, 77P = 192500 So, P = 2500 So, required interest = (10 X 2500 X 1) ÷ 100 = Rs. 250
(? × 3)2 - 85 = 115 × 5 + 69
25% of 250 + 32% of 200 = ? ÷ √ 16
√729 × 5 + 270 - 3 ÷ ∛27 + 4 × ? = 484
Find the value of 16 x [(8 - 5) of 12 ÷ 4].
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
15.8% of 9000 + 20.4% of 7500 = 30% of ?
(165 × 12) ÷ 45 + 110 = ? × 2
25.6% of 250 + √? = 119